Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Mixed Review Exercises - Page 639: 10

Answer

$\left\{\dfrac{4}{3}\right\}$

Work Step by Step

Expressing both sides of the given equation, $ 27^x=81 $, in the same base results to \begin{align*}\require{cancel} \left(3^3\right)^x&=3^4 \\ 3^{3x}&=3^4 &(\text{use }\left(x^m\right)^n=x^{mn}) .\end{align*} Since $x^m=x^n$ implies $m=n$, the equation above implies \begin{align*}\require{cancel} 3x&=4 .\end{align*} Using the properties of equality, the equation above is equivalent to \begin{align*}\require{cancel} \dfrac{\cancel3x}{\cancel3}&=\dfrac{4}{3} \\\\ x&=\dfrac{4}{3} .\end{align*} Hence, the solution set of the equation $ 27^x=81 $ is $ \left\{\dfrac{4}{3}\right\} $.
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