Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Mixed Review Exercises - Page 639: 11

Answer

$\left\{3\right\}$

Work Step by Step

Expressing both sides of the given equation, $ 2^{2x-3}=8 $, in the same base results to \begin{align*}\require{cancel} 2^{2x-3}&=2^3 .\end{align*} Since $x^m=x^n$ implies $m=n$, the equation above implies \begin{align*}\require{cancel} 2x-3&=3 .\end{align*} Using the properties of equality, the equation above is equivalent to \begin{align*}\require{cancel} 2x-3+3&=3+3 \\ 2x&=6 \\\\ \dfrac{\cancel2x}{\cancel2}&=\dfrac{6}{2} \\\\ x&=3 .\end{align*} Hence, the solution set of the equation $ 2^{2x-3}=8 $ is $ \left\{3\right\} $.
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