Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Chapter 9 Test - Page 640: 9

Answer

$\left\{-4\right\}$

Work Step by Step

Expressing both sides of the given equation, $ 5^x=\dfrac{1}{625} ,$ in the same base results to \begin{align*}\require{cancel} 5^x&=\dfrac{1}{5^4} \\\\ 5^x&=5^{-4} .\end{align*} Since $b^x=b^y$ implies $x=y$, the equation above implies \begin{align*}\require{cancel} x&=-4 .\end{align*} Hence, the solution set of the equation $ 5^x=\dfrac{1}{625} $ is $ \left\{-4\right\} $.
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