Answer
a) approximately $775$ millibars
b) approximately $265$ millibars
Work Step by Step
a) Using the given function, $
f(x)=1013e^{-0.0001341x}
$, with $x=2000$, then
\begin{align*}\require{cancel}
f(2000)&=1013e^{-0.0001341(2000)}
\\&\approx
1013(0.764755)
\\&\approx
775
.\end{align*}
Hence, the atmospheric pressure at $
2000$ $m$ is approximately $775$ millibars.
b) Using the given function, $
f(x)=1013e^{-0.0001341x}
$, with $x=10,000$, then
\begin{align*}\require{cancel}
f(2000)&=1013e^{-0.0001341(10000)}
\\&=
1013e^{-1.341}
\\&\approx
265
.\end{align*}
Hence, the atmospheric pressure at $
10,000$ $m$ is approximately $265$ millibars.