Answer
$9x^{2}-64$
Work Step by Step
From Page 301, we know that the product of a sum and difference of two terms $x$ and $y$ is given by the following equation: $(x+y)(x-y)=x^{2}-y^{2}$.
Therefore, $(3x-8)(3x+8)=(3x)^{2}-8^{2}=3^{2}x^{2}-64=9x^{2}-64$.
