Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises - Page 304: 15



Work Step by Step

Using the Distributive Property, the product of the given expression, $ (2t+3)(3t^2-4t-1) ,$ is \begin{array}{l}\require{cancel} 2t(3t^2)+2t(-4t)+2t(-1)+3(3t^2)+3(-4t)+3(-1) \\\\= 6t^3-8t^2-2t+9t^2-12t-3 \\\\= 6t^3+(-8t^2+9t^2)+(-2t-12t)-3 \\\\= 6t^3+t^2-14t-3 .\end{array}
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