## Intermediate Algebra (12th Edition)

D. $6x^{2}-23x+20$
We are given the expression $(2x-5)(3x-4)$. We can find the product of this expression using the FOIL method. First terms: $2x\times 3x=6x^{2}$ Outer terms: $2x\times-4=-8x$ Inner terms: $-5\times 3x=-15x$ Last terms: $-5\times-4=20$ Adding together: $6x^{2}+(-8x)+(-15x)+20=6x^{2}-8x-15x+20=6x^{2}-23x+20$