Answer
$32y^3+4y^2-6y$
Work Step by Step
Using the Distributive Property, the product of the given expression, $
2y(2y+1)(8y-3)
,$ is
\begin{array}{l}\require{cancel}
[2y(2y)+2y(1)](8y-3)
\\\\=
[4y^2+2y](8y-3)
\\\\=
4y^2(8y)+4y^2(-3)+2y(8y)+2y(-3)
\\\\=
32y^3-12y^2+16y^2-6y
\\\\=
32y^3+4y^2-6y
.\end{array}
