Answer
$6y^2+y-12$
Work Step by Step
Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method, the product of the binomials in the given expression, $
(2y+3)(3y-4)
,$ is
\begin{array}{l}\require{cancel}
2y(3y)+2y(-4)+3(3y)+3(-4)
\\\\=
6y^2-8y+9y-12
\\\\=
6y^2+y-12
.\end{array}