Answer
$6x^{2}+17xy+12y^{2}$
Work Step by Step
We are given the expression $(3x+4y)(2x+3y)$. We can find the product of this expression using the FOIL method.
First terms: $3x\times 2x=6x^{2}$
Outer terms: $3x\times3y=9xy$
Inner terms: $4y\times 2x=8xy$
Last terms: $4y\times3y=12y^{2}$
Adding together: $6x^{2}+9xy+8xy+12y^{2}=6x^{2}+17xy+12y^{2}$
