Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises - Page 304: 13



Work Step by Step

Using $a(b+c)=ab+ac$ or the Distributive Property, the product of the given expression, $ 6k^2(3k^2+2k+1) ,$ is \begin{array}{l}\require{cancel} 6k^2(3k^2)+6k^2(2k)+6k^2(1) \\\\= 18k^4+12k^3+6k^2 .\end{array}
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