Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - 3.1 Exercises - Page 227: 58

$x=0$ $y=0$

If we multiply the second equation by $3$, then we add the two equations, we can eliminate the $y$ from the system: $3x+3y=0$ $-2\times3x-3y=0\times3$ $3x-6x=0$ $x=0$ $3(0)+3y=0$ $y=0$ We have to check, if the solution is right. Substitute $x$ with 0 and $y$ with 0: $3(0)+3(0)=0$ $\checkmark$ $-2(0)-0=0$ $\checkmark$