Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - 3.1 Exercises: 50

Answer

$x=4$ $y=-5$

Work Step by Step

If we multiply the first equation by $-2$ second equation by $3$, then we add the two equations, we can eliminate the $y$ from the system: $4x\times(-2)+3\times(-2)y=1\times(-2)$ $3\times3x+2\times3y=2\times3$ $-8x+9x=4$ $x=4$ $4(4)+3y=1$ $y=-5$ We have to check, if the solution is right. Substitute $x$ with 4 and $y$ with -5: $4(4)+3(-5)=1$ $\checkmark$ $3(4)+2(-5)=2$ $\checkmark$
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