Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - 3.1 Exercises: 30


$x=3$ $y=-1$

Work Step by Step

First, we have to solve the first equation for $y$ and after that, we can substitute this expression in the second equation: $3x-y=10$ $y=3x-10$ $2x+5(3x-10)=1$ $17x-50=1$ $17x=51$ $x=3$ $y=3x-10=3(3)-10=-1$ We need to check, if it is the right solution, we substitute x with $3$ and y with $-1$: $3(3)-(-1)=10$ $\checkmark$ $2(3)+5(-1)=1$ $\checkmark$
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