Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - 3.1 Exercises - Page 227: 45


$x=2$ $y=-4$

Work Step by Step

If we add the two equations, we can eliminate the $x$ from the system: $-2x+3y=-16$ $2x-5y=24$ $3y-5y=8$ $y=-4$ $-2x+3(-4)=-16$ $x=2$ We have to check, if the solution is right. Substitute $x$ with 2 and $y$ with -4: $-2(2)+3(-4)=-16$ $\checkmark$ $2(2)-5(-4)=24$ $\checkmark$
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