Answer
$x=0$
$y=0$
Work Step by Step
If we multiply the first equation by $\frac{1}{3}$, the second one by $0.2$, then we add the two equations, we can eliminate the $y$ from the system:
$0.4\times \frac{1}{3}x+0.2\times \frac{1}{3}y=0\times \frac{1}{3}$
$\frac{1}{2}\times 0.2x-\frac{1}{3}\times0.2y=0\times 0.2$
$\frac{0.4}{3}x+0.1x=0$
$x=0$
$0.4(0)+0.2y=0$
$y=0$
We have to check, if the solution is right. Substitute $x$ with 0 and $y$ with 0:
$0.4(0)+0.2(0)=0$ $\checkmark$
$\frac{1}{2}(0)-\frac{1}{3}(0)=0$ $\checkmark$
