Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - 3.1 Exercises - Page 227: 41


$x=-8$ $y=4$

Work Step by Step

If we add the two equations, we can eliminate the $y$ from the system: $\frac{1}{2}x-\frac{1}{4}y=-5$ $\frac{1}{8}x+\frac{1}{4}y=0$ $\frac{5}{8}x=-5$ $x=-8$ $\frac{1}{8}(-8)+\frac{1}{4}y=0$ $y=4$ We have to check, if the solution is right. Substitute $x$ with -8 and $y$ with 4: $\frac{1}{2}(-8)-\frac{1}{4}(4)=-5$ $\checkmark$ $\frac{1}{8}(-8)+frac{1}{4}(4)=0$ $\checkmark$
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