Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - 3.1 Exercises - Page 227: 39

$x=4$ $y=2$

The first equation is already solved for $y$, then we have to substitute this expression into the second equation: $y=0.5x$ Second equation: $1.5x-0.5(0.5x)=5.0$ $1.25x=5.0$ $x=\frac{5}{1.25}=4$ $y=0.5(4)=2$ We have to check, if the solution is right. Substitute $x$ with 4 and $y$ with 2: $2=0.5(4)$ $\checkmark$ $1.5(4)-0.5(2)=6-1=5.0$ $\checkmark$