Answer
$0$
Work Step by Step
We know that for a matrix
$
\left[\begin{array}{rrr}
a & b & c \\
d &e & f \\
g &h & i \\
\end{array} \right]
$
the determinant, $D=a(ei-fh)-b(di-fg)+c(dh-eg).$
Hence, here
$D=2(1\cdot2-2\cdot(-2))-(-1)((-3)\cdot2-2\cdot0)+(-1)((-3)\cdot(-2)-1\cdot0)=2(6)+1(-6)+(-1)(6)=12-6-6=0.$
