Answer
The linear system does not have a unique solution.
Work Step by Step
The coefficient matrix is $A=\left[\begin{array}{cc}3 & -4 \\ \frac{2}{3} & \frac{-8}{9}\end{array}\right] .$ The determinant of the matrix A is
$$
\operatorname{det} A=\left|\begin{array}{cc}
3 & -4 \\
\frac{2}{3} & \frac{-8}{9}
\end{array}\right|=\frac{-24}{9}+\frac{8}{3}=\frac{-24}{9}+\frac{24}{9}=Z E R O
$$
Thus, matrix A is singular and the linear system does not have a unique solution.
