Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 1 - Systems of Linear Equations - 1.1 Introduction to Systems of Linear Equations - 1.1 Exercises - Page 10: 49

Answer

The system is inconsistent

Work Step by Step

3$x_{1}$ + 2$x_{2}$ + 4$x_{3}$ = 1 $x_{1}$ + $x_{2}$ - 2$x_{3}$ = 3 2$x_{1}$ - 3$x_{2}$ + 6$x_{3}$ = 8 $R_{1}$↔$R_{2}$ $x_{1}$ + $x_{2}$ - 2$x_{3}$ = 3 3$x_{1}$ + 2$x_{2}$ + 4$x_{3}$ = 1 2$x_{1}$ - 3$x_{2}$ + 6$x_{3}$ = 8 -3$R_{1}$+$R_{2}$→$R_{2}$ -2$R_{1}$+$R_{1}$→$R_{1}$ $x_{1}$ + $x_{2}$ - 2$x_{3}$ = 3 -5$x_{2}$ + 10$x_{3}$ = -8 -5$x_{2}$ + 10$x_{3}$ = 2 -$R_{2}$+$R_{3}$→$R_{3}$ $x_{1}$ + $x_{2}$ - 2$x_{3}$ = 3 -5$x_{2}$ + 10$x_{3}$ = -8 0 = 10 0$\ne$10, so the system has no solution.
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