## Elementary Linear Algebra 7th Edition

$\frac{x-2}{4}+\frac{y-1}{3}=2$ $x-3y=20$ Express x in terms of y. $x=20+3y$ Substitute for x in the first equation and solve for y. $\frac{(20+3y)-2}{4}+\frac{y-1}{3}=2$ $\rightarrow$ Simplify. $\frac{18+3y}{4}+\frac{y-1}{3}=2$ $\rightarrow$ Multiply both sides by 12 to remove the fractions. $3(18+3y)+ 4(y-1)=24$ $\rightarrow$ Simplify. $54 + 9y + 4y -4 = 24$ $13y = -26$ $y = -2$ Substitute for y and solve for x. $x-3y = 20$ $x-3(-2)=20$ $x = 14$