Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 1 - Systems of Linear Equations - 1.1 Introduction to Systems of Linear Equations - 1.1 Exercises - Page 10: 43

Answer

x = 14 y = -2 (14, -2)

Work Step by Step

$\frac{x-2}{4}+\frac{y-1}{3}=2$ $x-3y=20$ Express x in terms of y. $x=20+3y$ Substitute for x in the first equation and solve for y. $\frac{(20+3y)-2}{4}+\frac{y-1}{3}=2$ $\rightarrow$ Simplify. $\frac{18+3y}{4}+\frac{y-1}{3}=2$ $\rightarrow$ Multiply both sides by 12 to remove the fractions. $3(18+3y)+ 4(y-1)=24$ $\rightarrow$ Simplify. $54 + 9y + 4y -4 = 24$ $13y = -26$ $y = -2$ Substitute for y and solve for x. $x-3y = 20$ $x-3(-2)=20$ $x = 14$
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