Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 1 - Systems of Linear Equations - 1.1 Introduction to Systems of Linear Equations - 1.1 Exercises: 26

Answer

There is one solution to the system. $x_{1} = 9$ $x_{2} = 3$

Work Step by Step

From Equation 2, we can solve that $x_{2} = 3$ by dividing both sides of the equation by 3. We can then substitute $x_{2} = 3$ into Equation 1. This gives the equation $2x_{1} -4 * 3 = 9$ . Solving this equation gives us $x_{1} = 9$. Therefore, the only solution is as follows. $x_{1} = 9$ $x_{2} = 3$
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