## Elementary Linear Algebra 7th Edition

There is one solution to the system. $x_{1} = 9$ $x_{2} = 3$
From Equation 2, we can solve that $x_{2} = 3$ by dividing both sides of the equation by 3. We can then substitute $x_{2} = 3$ into Equation 1. This gives the equation $2x_{1} -4 * 3 = 9$ . Solving this equation gives us $x_{1} = 9$. Therefore, the only solution is as follows. $x_{1} = 9$ $x_{2} = 3$