Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 1 - Systems of Linear Equations - 1.1 Introduction to Systems of Linear Equations - 1.1 Exercises - Page 10: 20

Answer

$x=7$ $y=1$ (7, 1)

Work Step by Step

$\frac{x-1}{2}+\frac{y+2}{3}=4$ $x-2y=5$ Multiply both sides of the first equation by 6 to get rid of the fractions. $\frac{x-1}{2}*6+\frac{y+2}{3}*6=4*6$ $3x-3+2y+4=24$ $3x + 2y = 23$ Add the second equation to the multiplied first equation. $3x + 2y +(x-2y)=23+5$ $3x+x+2y-2y=28$ $4x=28$ $x=7$ Substitute x in the second equation to get y. $7-2y=5$ $-2y=-2$ $y=1$
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