## Elementary Linear Algebra 7th Edition

$x=7$ $y=1$ (7, 1)
$\frac{x-1}{2}+\frac{y+2}{3}=4$ $x-2y=5$ Multiply both sides of the first equation by 6 to get rid of the fractions. $\frac{x-1}{2}*6+\frac{y+2}{3}*6=4*6$ $3x-3+2y+4=24$ $3x + 2y = 23$ Add the second equation to the multiplied first equation. $3x + 2y +(x-2y)=23+5$ $3x+x+2y-2y=28$ $4x=28$ $x=7$ Substitute x in the second equation to get y. $7-2y=5$ $-2y=-2$ $y=1$