Chapter 1 - Systems of Linear Equations - 1.1 Introduction to Systems of Linear Equations - 1.1 Exercises - Page 10: 12

$x = -1$ $y = 1$ (-1, 1)

$x + 3y = 2$ $-x + 2y = 3$ Add the second equation to the first one $x + 3y - x + 2y = 2 + 3$ $5y = 5$ (divide both sides by 5) $y = 1$ Substitute $y$ in the first equation to get $x$ $x + 3*1 = 2$ $x = -1$