## Elementary Linear Algebra 7th Edition

$x = 3.6$ $y = 0.6$ (3.6, 0.6)
$\frac{x}{4}+\frac{y}{6}=1$ $x-y=3$ Step #1 - Multiply the first equation by 12: $3x + 2y = 12$ $x - y = 3$ Step #2 - Multiply the second equation by 3: $3x + 2y = 12$ $3x - 3y = 9$ Step #3 - Subtract the first equation from the second equation: $3x - 3y - (3x + 2y) = 9 - 12$ $-5y = -3$ $y = \frac{3}{5} = 0.6$ Step #4 - Substitute $y$ to get $x$: $x-y=3$ $x-0.6=3$ $x=3.6$