Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 1 - Systems of Linear Equations - 1.1 Introduction to Systems of Linear Equations - 1.1 Exercises: 27

Answer

There is one solution to the system. $x = 3/2$ $y = 3/2$ $z = 0$

Work Step by Step

From Equation 3, we can see that $z = 0$. Substituting $z = 0$ into Equation 2 gives us $2y = 3$. We can then conclude that $y = 3/2$. By substituting $z = 0$ and $y = 3/2$ into Equation 1, we can see that $-x + 3/2 = 0$. We can solve this equation to then find that $x = 3/2$.
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