Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Review Exercises: Chapter 4: 9

Answer

$n^{12}$

Work Step by Step

Using the laws of exponents, the given expression, $ n^3\cdot n^8\cdot n ,$ simplifies to \begin{array}{l}\require{cancel} n^{3+8+1} \\\\= n^{12} .\end{array}
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