Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Review Exercises: Chapter 4: 21

Answer

$\dfrac{1}{16}$

Work Step by Step

Using the laws of exponents, the given expression, $ 4^5\cdot 4^{-7} ,$ simplifies to \begin{array}{l}\require{cancel} 4^{5+(-7)} \\\\= 4^{-2} \\\\= \dfrac{1}{4^{2}} \\\\= \dfrac{1}{16} .\end{array}
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