Answer
$14a^5-2a^2-a-\frac{2}{3}$
Work Step by Step
Combine like terms to obtain:
$=(20a^5-6a^5)-2a^2-a+(\frac{1}{3}-1)
\\=14a^5-2a^2-a+(\frac{1}{3}-\frac{3}{3})
\\=14a^5-2a^2-a-\frac{2}{3}$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 4 - Polynomials - Review Exercises: Chapter 4 - Page 298: 38
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