## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\color{blue}{2.09 \times 10^4}$
Multiply the corresponding parts (multiply the constants together and the powers of 10 together) to obtain: $=(3.8 \times 5.5) \times (10^4 \times 10^{-1}) \\=20.9 \times 10^{4+(-1)} \\=20.9 \times 10^3$ Write $20.9$ as $2.09 \cdot 10^1$ to obtain: $=(2.09\cdot 10^1) \times 10^3 \\=2.09 \times 10^{3+1} \\=\color{blue}{2.09 \times 10^4}$