Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Review Exercises: Chapter 4: 29

Answer

$\color{blue}{5.12 \times 10^{-5}}$

Work Step by Step

Divide the corresponding parts (divide the constants together and the powers of 10 together) to obtain: $=\dfrac{1.28}{2.5} \times \dfrac{10^{-8}}{10^{-4}} \\=0.512 \times \dfrac{10^{-8}}{10^{-4}}$ Use the quotient rule for exponents to obtain: $=0.512 \times 10^{-8-(-4)} \\=0.512 \times 10^{-8+4} \\=0.512 \times 10^{-4}$ Write $0.512$ as $5.12 \cdot 10^{-1}$ to obtain: $=(5.12\cdot 10^{-1}) \times 10^{-4} \\=5.12 \times 10^{-1+(-4)} \\=\color{blue}{5.12 \times 10^{-5}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.