Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Review Exercises: Chapter 4 - Page 298: 17

Answer

$a^{7}b^{6}$

Work Step by Step

Using the laws of exponents, the given expression, $ (a^2b)(ab)^5 ,$ simplifies to \begin{array}{l}\require{cancel} (a^2b)(a^5b^5) \\\\= a^{2+5}b^{1+5} \\\\= a^{7}b^{6} .\end{array}
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