Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Review Exercises: Chapter 4 - Page 298: 40

Answer

$16$

Work Step by Step

Substitute the given value of $x$ to obtain: $x^2-3x+6 \\=(-2)^2-3(-2)+6 \\=4-(-6)+6 \\=4+6+6 \\=16$
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