Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.6 Quadratic Functions and Their Graphs - 11.6 Exercise Set - Page 741: 73

Answer

$f(x)=-2x^{2}-5$

Work Step by Step

The equation of the parabola will be in the form $f(x)=a(x-h)^{2}+k$ For $a\gt 0$, the minimum function value is $k$. For $a\lt 0$, the maximum function value is $k.$ Here, the maximum is $(0,-5)$, which means $a$ is negative and $-5$ is the maximum function value. Therefore the shape of the parabola is $f(x)=-2x^{2}$. $f(x)=a(x-h)^{2}+k$ Substitute $a=-2,h=0,k=-5$ $f(x)=-2x^{2}-5$
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