## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

The vertex is $(0.01,\sqrt{15})$ The axis of symmetry is $x=0.01.$ The minimum function value is $\sqrt{15}.$
$f(x)=2\pi(x-0.01)^{2}+\sqrt{15}$ $a=2\pi$ $h=0.01$ $k=\sqrt{15}$ The vertex is $(h, k)$, and the axis of symmetry is $x=h.$ For $a\gt 0$, the minimum function value is $k$. For $a\lt 0$, the maximum function value is $k.$ --- The vertex is $(0.01,\sqrt{15})$ The axis of symmetry is $x=0.01.$ Since $a\gt 0$, the minimum function value is $\sqrt{15}.$