Answer
The vertex is $(0.01,\sqrt{15})$
The axis of symmetry is $x=0.01.$
The minimum function value is $\sqrt{15}.$
Work Step by Step
$f(x)=2\pi(x-0.01)^{2}+\sqrt{15}$
$ a=2\pi$
$h=0.01$
$k=\sqrt{15}$
The vertex is $(h, k)$, and the axis of symmetry is $x=h.$
For $a\gt 0$, the minimum function value is $k$.
For $a\lt 0$, the maximum function value is $k.$
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The vertex is $(0.01,\sqrt{15})$
The axis of symmetry is $x=0.01.$
Since $a\gt 0$, the minimum function value is $\sqrt{15}.$