Answer
The vertex is $(1,-10)$
The axis of symmetry is $x=1.$
The minimum function value is $-10$.
Work Step by Step
$f(x)=2(x-1)^{2}-10$
$a=2$
$h=1$
$k=-10$
The vertex is $(h, k)$, and the axis of symmetry is $x=h.$
For $a\gt 0$, the minimum function value is $k$.
For $a\lt 0$, the maximum function value is $k.$
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The vertex is $(1,-10)$
The axis of symmetry is $x=1.$
Since $a\gt 0$, the minimum function value is $-10$.