Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.6 Quadratic Functions and Their Graphs - 11.6 Exercise Set - Page 741: 53

Answer

The vertex is $(-2.25,-\pi)$ The axis of symmetry is $x=-2.25.$ The maximum function value is $-\pi.$

Work Step by Step

$ f(x)=-\sqrt{2}(x+2.25)^{2}-\pi$ $a=-\sqrt{2}$ $h=-2.25$ $ k=-\pi$ The vertex is $(h, k)$, and the axis of symmetry is $x=h.$ For $a\gt 0$, the minimum function value is $k$. For $a\lt 0$, the maximum function value is $k.$ --- The vertex is $(-2.25,-\pi)$ The axis of symmetry is $x=-2.25.$ Since $a\lt 0$, the maximum function value is $-\pi.$
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