## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

The graph of $f(x)=a(x-h)^{2}+k$ has the same shape as the graph of $y=a(x-h)^{2}.$ If $k$ is positive, the graph of $y=a(x-h)^{2}$ is shifted $k$ units up. If $k$ is negative, the graph of $y=a(x-h)^{2}$ is shifted $|k|$ units down. The vertex is $(h, k)$, and the axis of symmetry is $x=h.$ For $a\gt 0$, the minimum function value is $k$. For $a\lt 0$, the maximum function value is $k.$ --- $k=-4$; shifted $4$ units down. $h=2$ $a=-1$; opens downward The vertex is $(2,-4)$. The axis of symmetry is $x=2.$ Since $a\lt 0$, the maximum function value is $-1$ Make a table of function values and plot the points, and join with a smooth curve.