Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.6 Quadratic Functions and Their Graphs - 11.6 Exercise Set - Page 741: 68


$f(x)=\displaystyle \frac{3}{5}(x-9)^{2}-6$

Work Step by Step

$f(x)=\displaystyle \frac{3}{5}x^{2}$ In order to have a vertex in the point $(9,-6)$, this function needs to be moved $9$ units to the right and $6$ units down. $f(x)=a(x-h)^{2}+k$ Substitute $a=\displaystyle \frac{3}{5},h=9,k=-6$ $f(x)=\displaystyle \frac{3}{5}(x-9)^{2}-6$
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