Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.2 The Quadratic Formula - 11.2 Exercise Set - Page 713: 8


$x=2$ or $x=\displaystyle \frac{1}{3}$

Work Step by Step

$ 3x^{2}-7x+2=0\qquad$... solve with the Quadractic formula. $a=3,\ b=-7,\ c=2$ $ x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\qquad$... substitute $b$ for $-7,\ a$ for $3$ and $c$ for $2$. $ x=\displaystyle \frac{-(-7)\pm\sqrt{(-7)^{2}-4\cdot(3)\cdot 2}}{2\cdot 3}\qquad$... simplify. $x=\displaystyle \frac{7\pm\sqrt{49-24}}{6}$ $x=\displaystyle \frac{7\pm\sqrt{25}}{6}$ $ x=\displaystyle \frac{7\pm 5}{6}\qquad$... the symbol $\pm$ indicates two solutions. $x=\displaystyle \frac{7+5}{6}$ or $x=\displaystyle \frac{7-5}{6}$ $x=2$ or $x=\displaystyle \frac{1}{3}$
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