Answer
$$x=1.457, -.457$$
Work Step by Step
The quadratic formula states:
$$ x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
Solving by using the quadratic formula to approximate the solution, we find:
$$ x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:3\left(-2\right)}}{2\cdot \:3} \\ x=\frac{3+\sqrt{33}}{6},\:x=\frac{3-\sqrt{33}}{6}\\ x=1.457, -.457$$
