Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.2 The Quadratic Formula - 11.2 Exercise Set - Page 713: 40



Work Step by Step

Solving by plugging in the given value and then using the quadratic formula, we find: $$ 4x^2-2x-3=0\\ x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:4\left(-3\right)}}{2\cdot \:4}\\ x=\frac{1+\sqrt{13}}{4},\:x=\frac{1-\sqrt{13}}{4}$$
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