Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.2 The Quadratic Formula - 11.2 Exercise Set - Page 713: 27


$x=\displaystyle \frac{2}{5}$

Work Step by Step

$ 25x^{2}-20x+40\qquad$... solve with the Quadractic formula. $a=25,\ b=-20,\ c=4$ $ x=\displaystyle \frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\qquad$... substitute $b$ for $-20,\ a$ for $25$ and $c$ for $4$. $ x=\displaystyle \frac{-(-20)\pm\sqrt{(-20)^{2}-4\cdot(4)\cdot 25}}{2\cdot 25}\qquad$... simplify. $x=\displaystyle \frac{20\pm\sqrt{400-400}}{50}$ $x=\displaystyle \frac{20\pm\sqrt{0}}{50}$ $x=\displaystyle \frac{20}{50}$ $x=\displaystyle \frac{2}{5}$
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