Chapter 11 - Quadratic Functions and Equations - 11.2 The Quadratic Formula - 11.2 Exercise Set - Page 713: 18

$$x=\frac{9-\sqrt{41}}{4},\:x=\frac{9+\sqrt{41}}{4}$$

Solving using the quadratic formula, we find: $$ \frac{9}{x}x^2-2x^2=\frac{5}{x^2}x^2\\ 9x-2x^2=5 \\ x_{1,\:2}=\frac{-9\pm \sqrt{9^2-4\left(-2\right)\left(-5\right)}}{2\left(-2\right)}\\ x=\frac{9-\sqrt{41}}{4},\:x=\frac{9+\sqrt{41}}{4}$$