Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10: 9

Answer

$\dfrac{10}{11}$

Work Step by Step

Using exponents and radicals, the given expression simplifies to \begin{array}{l}\require{cancel} \sqrt{\dfrac{100}{121}} \\\\= \sqrt{\left( \dfrac{10}{11} \right)^2} \\\\= \dfrac{10}{11} .\end{array}
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