## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10 - Page 693: 9

#### Answer

$\dfrac{10}{11}$

#### Work Step by Step

Using exponents and radicals, the given expression simplifies to \begin{array}{l}\require{cancel} \sqrt{\dfrac{100}{121}} \\\\= \sqrt{\left( \dfrac{10}{11} \right)^2} \\\\= \dfrac{10}{11} .\end{array}

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