Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10 - Page 693: 9

Answer

$\dfrac{10}{11}$

Work Step by Step

Using exponents and radicals, the given expression simplifies to \begin{array}{l}\require{cancel} \sqrt{\dfrac{100}{121}} \\\\= \sqrt{\left( \dfrac{10}{11} \right)^2} \\\\= \dfrac{10}{11} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.