Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10: 10

Answer

$-0.6$

Work Step by Step

Using exponents and radicals, the given expression simplifies to \begin{array}{l}\require{cancel} -\sqrt{0.36} \\\\= -\sqrt{(0.6)^2} \\\\= -0.6 .\end{array}
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