# Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10: 35

$-1$

#### Work Step by Step

Using the product of the sum and difference of like terms which is given by $(a+b)(a-b)=a^2-b^2,$ the given expression is equivalent to \begin{array}{l}\require{cancel} (3+\sqrt{10})(3-\sqrt{10}) \\\\= (3)^2-(\sqrt{10})^2 \\\\= 9-10 \\\\= -1 .\end{array}

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