Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10: 35

Answer

$-1$

Work Step by Step

Using the product of the sum and difference of like terms which is given by $(a+b)(a-b)=a^2-b^2,$ the given expression is equivalent to \begin{array}{l}\require{cancel} (3+\sqrt{10})(3-\sqrt{10}) \\\\= (3)^2-(\sqrt{10})^2 \\\\= 9-10 \\\\= -1 .\end{array}
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