Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10 - Page 693: 23

Answer

$f(x)=5|(x-6)|$

Work Step by Step

Using $\sqrt[n]{x^n}=|x|$ if $n$ is even and $\sqrt[n]{x^n}=x$ if $n$ is odd, then \begin{array}{l}\require{cancel} f(x)=\sqrt{25(x-6)^2} \\\\ f(x)=\sqrt{[5(x-6)]^2} \\\\ f(x)=|5(x-6)| \\\\ f(x)=|5|\cdot|(x-6)| \\\\ f(x)=5|(x-6)| .\end{array}

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