Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Review Exercises: Chapter 10 - Page 693: 44



Work Step by Step

Raising both sides to the third power and isolating the variable, the given equation is equivalent to \begin{array}{l}\require{cancel} (x+1)^{1/3}=-5 \\\\ \left[(x+1)^{1/3}\right]^3=(-5)^3 \\\\ x+1=-125 \\\\ x=-125-1 \\\\ x=-126 .\end{array} Upon checking, $ x=-126 $ satisfies the original equation.
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